When fully charged, if a capacitor discharges through a patient in 10 ms, what is the average electrical current through the paddles if the charge is 75 mC?

To determine the average electrical current through the paddles when a capacitor discharges, we can use the formula for current, which is defined as the charge transferred (Q) divided by the time (t) it takes for that charge to transfer.

In this case, the charge (Q) is given as 75 mC, which is equivalent to 0.075 C when converted to coulombs. The time (t) for the discharge is given as 10 ms, which is equivalent to 0.01 seconds when converted to seconds.

Using the formula for current:

[ I = \frac{Q}{t} ]

Substituting the values we have:

[ I = \frac{0.075 , \text{C}}{0.01 , \text{s}} = 7.5 , \text{A} ]

This calculation indicates that the average electrical current through the paddles during the discharge of the capacitor is 7.5 A.

The result reflects the correct interpretation of charge and time in the context of electrical currents, aligning with the fundamental relationship defined by Ohm's law and the principles of electrical circuits. Other values provided would suggest incorrect calculations or misunderstandings in the